MoreEnumerableTakeEveryTSource Method |
Returns every N-th element of a sequence.
Namespace: MoreLinqAssembly: MoreLinq (in MoreLinq.dll) Version: 1.4.18916.0 (1.4.18916.839)
Syntax public static IEnumerable<TSource> TakeEvery<TSource>(
this IEnumerable<TSource> source,
int step
)
<ExtensionAttribute>
Public Shared Function TakeEvery(Of TSource) (
source As IEnumerable(Of TSource),
step As Integer
) As IEnumerable(Of TSource)
public:
[ExtensionAttribute]
generic<typename TSource>
static IEnumerable<TSource>^ TakeEvery(
IEnumerable<TSource>^ source,
int step
)
[<ExtensionAttribute>]
static member TakeEvery :
source : IEnumerable<'TSource> *
step : int -> IEnumerable<'TSource>
Parameters
- source
- Type: System.Collections.GenericIEnumerableTSource
Source sequence - step
- Type: SystemInt32
Number of elements to bypass before returning the next element.
Type Parameters
- TSource
- Type of the source sequence
Return Value
Type:
IEnumerableTSource
A sequence with every N-th element of the input sequence.
Usage Note
In Visual Basic and C#, you can call this method as an instance method on any object of type
IEnumerableTSource. When you use instance method syntax to call this method, omit the first parameter. For more information, see
Extension Methods (Visual Basic) or
Extension Methods (C# Programming Guide).
Remarks
This operator uses deferred execution and streams its results.
Examples int[] numbers = { 1, 2, 3, 4, 5 };
IEnumerable<int> result = numbers.TakeEvery(2);
The
result variable, when iterated over, will yield 1, 3 and 5, in turn.
See Also