MoreEnumerableGenerateTResult Method |
Returns a sequence of values consecutively generated by a generator function.
Namespace: MoreLinqAssembly: MoreLinq (in MoreLinq.dll) Version: 1.4.18916.0 (1.4.18916.839)
Syntax public static IEnumerable<TResult> Generate<TResult>(
TResult initial,
Func<TResult, TResult> generator
)
Public Shared Function Generate(Of TResult) (
initial As TResult,
generator As Func(Of TResult, TResult)
) As IEnumerable(Of TResult)
public:
generic<typename TResult>
static IEnumerable<TResult>^ Generate(
TResult initial,
Func<TResult, TResult>^ generator
)
static member Generate :
initial : 'TResult *
generator : Func<'TResult, 'TResult> -> IEnumerable<'TResult>
Parameters
- initial
- Type: TResult
Value of first element in sequence - generator
- Type: SystemFuncTResult, TResult
Generator function which takes the previous series element and uses it to generate the next element.
Type Parameters
- TResult
- Type of elements to generate.
Return Value
Type:
IEnumerableTResultA sequence containing the generated values.
Remarks
This function defers element generation until needed and streams the results.
Examples IEnumerable<int> result = Sequence.Generate(2, n => n * n).Take(5);
The
result variable, when iterated over, will yield 2, 4, 16, 256, and 65536, in turn.
See Also