MoreEnumerable.Shuffle<T> Method (IEnumerable<T>, Random) |
Returns a sequence of elements in random order from the original
sequence. An additional parameter specifies a random generator to be
used for the random selection algorithm.
Namespace:
MoreLinq
Assembly:
MoreLinq (in MoreLinq.dll) Version: 3.3.1+b77df70598ab84c28cd43dcf74594024b6d575e1
Syntaxpublic static IEnumerable<T> Shuffle<T>(
this IEnumerable<T> source,
Random rand
)
<ExtensionAttribute>
Public Shared Function Shuffle(Of T) (
source As IEnumerable(Of T),
rand As Random
) As IEnumerable(Of T)
public:
[ExtensionAttribute]
generic<typename T>
static IEnumerable<T>^ Shuffle(
IEnumerable<T>^ source,
Random^ rand
)
[<ExtensionAttribute>]
static member Shuffle :
source : IEnumerable<'T> *
rand : Random -> IEnumerable<'T>
Parameters
- source
- Type: System.Collections.Generic.IEnumerable<T>
The sequence from which to return random elements. - rand
- Type: System.Random
A random generator used as part of the selection algorithm.
Type Parameters
- T
- The type of source sequence elements.
Return Value
Type:
IEnumerable<T>
A sequence of elements
source randomized in
their order.
Usage Note
In Visual Basic and C#, you can call this method as an instance method on any object of type
IEnumerable<T>. When you use instance method syntax to call this method, omit the first parameter. For more information, see
Extension Methods (Visual Basic) or
Extension Methods (C# Programming Guide).
Remarks
This method uses deferred execution and streams its results. The
source sequence is entirely buffered before the results are
streamed.
See Also