AggregateRightExtensionAggregateRightTSource, TAccumulate Method (IEnumerableTSource, TAccumulate, FuncTSource, TAccumulate, TAccumulate) | 
  
    Namespace: 
   MoreLinq.Extensions
    Assembly:
   MoreLinq (in MoreLinq.dll) Version: 3.2.0+5205ea241d72b079436060d330cd5c2eae7cdcdf
Syntaxpublic static TAccumulate AggregateRight<TSource, TAccumulate>(
	this IEnumerable<TSource> source,
	TAccumulate seed,
	Func<TSource, TAccumulate, TAccumulate> func
)
<ExtensionAttribute>
Public Shared Function AggregateRight(Of TSource, TAccumulate) ( 
	source As IEnumerable(Of TSource),
	seed As TAccumulate,
	func As Func(Of TSource, TAccumulate, TAccumulate)
) As TAccumulate
public:
[ExtensionAttribute]
generic<typename TSource, typename TAccumulate>
static TAccumulate AggregateRight(
	IEnumerable<TSource>^ source, 
	TAccumulate seed, 
	Func<TSource, TAccumulate, TAccumulate>^ func
)
[<ExtensionAttribute>]
static member AggregateRight : 
        source : IEnumerable<'TSource> * 
        seed : 'TAccumulate * 
        func : Func<'TSource, 'TAccumulate, 'TAccumulate> -> 'TAccumulate 
Parameters
- source
 - Type: System.Collections.GenericIEnumerableTSource
Source sequence. - seed
 - Type: TAccumulate
The initial accumulator value. - func
 - Type: SystemFuncTSource, TAccumulate, TAccumulate
A right-associative accumulator function to be invoked on each element. 
Type Parameters
- TSource
 - The type of the elements of source.
 - TAccumulate
 - The type of the accumulator value.
 
Return Value
Type: 
TAccumulateThe final accumulator value.
Usage Note
In Visual Basic and C#, you can call this method as an instance method on any object of type 
IEnumerableTSource. When you use instance method syntax to call this method, omit the first parameter. For more information, see 
Extension Methods (Visual Basic) or 
Extension Methods (C# Programming Guide).
Remarks
            This operator executes immediately.
            
Examplesvar numbers = Enumerable.Range(1, 5);
string result = numbers.AggregateRight("6", (a, b) => string.Format("({0}/{1})", a, b));
            The 
result variable will contain 
"(1/(2/(3/(4/(5/6)))))".
            
See Also