| MoreEnumerableGenerateTResult Method  | 
 
            Returns a sequence of values consecutively generated by a generator function.
            
 
    Namespace: 
   MoreLinq
    Assembly:
   MoreLinq (in MoreLinq.dll) Version: 2.4.0
 Syntax
Syntaxpublic static IEnumerable<TResult> Generate<TResult>(
	TResult initial,
	Func<TResult, TResult> generator
)
Public Shared Function Generate(Of TResult) ( 
	initial As TResult,
	generator As Func(Of TResult, TResult)
) As IEnumerable(Of TResult)
public:
generic<typename TResult>
static IEnumerable<TResult>^ Generate(
	TResult initial, 
	Func<TResult, TResult>^ generator
)
static member Generate : 
        initial : 'TResult * 
        generator : Func<'TResult, 'TResult> -> IEnumerable<'TResult> 
Parameters
- initial
- Type: TResult
 Value of first element in sequence
- generator
- Type: SystemFuncTResult, TResult
 Generator function which takes the previous series element and uses it to generate the next element.
Type Parameters
- TResult
- Type of elements to generate.
Return Value
Type: 
IEnumerableTResultA sequence containing the generated values.
 Remarks
Remarks
            This function defers element generation until needed and streams the results.
            
 Examples
ExamplesIEnumerable<int> result = Sequence.Generate(2, n => n * n).Take(5);
            The 
result variable, when iterated over, will yield 2, 4, 16, 256, and 65536, in turn.
            
 See Also
See Also