MoreEnumerable.TakeEvery(TSource) Method

MoreEnumerableTakeEveryTSource Method

Returns every N-th element of a sequence.

Namespace: MoreLinq
Assembly: MoreLinq (in MoreLinq.dll) Version: 2.1.0

Syntax

public static IEnumerable<TSource> TakeEvery<TSource>(
	this IEnumerable<TSource> source,
	int step
)

<ExtensionAttribute>
Public Shared Function TakeEvery(Of TSource) ( 
	source As IEnumerable(Of TSource),
	step As Integer
) As IEnumerable(Of TSource)

public:
[ExtensionAttribute]
generic<typename TSource>
static IEnumerable<TSource>^ TakeEvery(
	IEnumerable<TSource>^ source, 
	int step
)

[<ExtensionAttribute>]
static member TakeEvery : 
        source : IEnumerable<'TSource> * 
        step : int -> IEnumerable<'TSource>

Parameters

source: Type: System.Collections.GenericIEnumerableTSource
Source sequence
step: Type: SystemInt32
Number of elements to bypass before returning the next element.

Type Parameters

TSource: Type of the source sequence

Return Value

Type: IEnumerableTSource
A sequence with every N-th element of the input sequence.

Usage Note

In Visual Basic and C#, you can call this method as an instance method on any object of type IEnumerableTSource. When you use instance method syntax to call this method, omit the first parameter. For more information, see Extension Methods (Visual Basic) or Extension Methods (C# Programming Guide).

Remarks

This operator uses deferred execution and streams its results.

Examples

Copy

int[] numbers = { 1, 2, 3, 4, 5 };
IEnumerable<int> result = numbers.TakeEvery(2);

The result variable, when iterated over, will yield 1, 3 and 5, in turn.

Reference

MoreEnumerable Class

MoreLinq Namespace