FirstExtension.First<T> Method |
Returns the first element of a sequence.
Namespace:
MoreLinq.Extensions
Assembly:
MoreLinq (in MoreLinq.dll) Version: 3.3.1+b77df70598ab84c28cd43dcf74594024b6d575e1
Syntaxpublic static T First<T>(
this IExtremaEnumerable<T> source
)
<ExtensionAttribute>
Public Shared Function First(Of T) (
source As IExtremaEnumerable(Of T)
) As T
public:
[ExtensionAttribute]
generic<typename T>
static T First(
IExtremaEnumerable<T>^ source
)
[<ExtensionAttribute>]
static member First :
source : IExtremaEnumerable<'T> -> 'T
Parameters
- source
- Type: MoreLinq.IExtremaEnumerable<T>
The input sequence.
Type Parameters
- T
-
The type of the elements of source.
Return Value
Type:
T
The first element of the input sequence.
Usage Note
In Visual Basic and C#, you can call this method as an instance method on any object of type
IExtremaEnumerable<T>. When you use instance method syntax to call this method, omit the first parameter. For more information, see
Extension Methods (Visual Basic) or
Extension Methods (C# Programming Guide).
ExceptionsException | Condition |
---|
InvalidOperationException |
The input sequence is empty. |
See Also