MoreEnumerableSegmentT(IEnumerableT, FuncT, Int32, Boolean) Method
Divides a sequence into multiple sequences by using a segment detector based on the original sequence
Namespace: MoreLinqAssembly: MoreLinq (in MoreLinq.dll) Version: 4.1.0+0e154ef592f33ce0f6f3d534a9eedee273f0ce72
public static IEnumerable<IEnumerable<T>> Segment<T>(
this IEnumerable<T> source,
Func<T, int, bool> newSegmentPredicate
)
<ExtensionAttribute>
Public Shared Function Segment(Of T) (
source As IEnumerable(Of T),
newSegmentPredicate As Func(Of T, Integer, Boolean)
) As IEnumerable(Of IEnumerable(Of T))
public:
[ExtensionAttribute]
generic<typename T>
static IEnumerable<IEnumerable<T>^>^ Segment(
IEnumerable<T>^ source,
Func<T, int, bool>^ newSegmentPredicate
)
[<ExtensionAttribute>]
static member Segment :
source : IEnumerable<'T> *
newSegmentPredicate : Func<'T, int, bool> -> IEnumerable<IEnumerable<'T>>
- source IEnumerableT
- The sequence to segment
- newSegmentPredicate FuncT, Int32, Boolean
- A function, which returns true if the given element or index indicate a new segment, and false otherwise
- T
- The type of the elements in the sequence
IEnumerableIEnumerableTA sequence of segment, each of which is a portion of the original sequenceIn Visual Basic and C#, you can call this method as an instance method on any object of type
IEnumerableT. When you use instance method syntax to call this method, omit the first parameter. For more information, see
Extension Methods (Visual Basic) or
Extension Methods (C# Programming Guide).